Chemical Thermodynamics Question 376

Question: The enthalpy of neutralisation of $ NH_4OH $ and $ CH_3COOH $ is $ -10.5kcalmo{{l}^{-1}} $ and enthalpy of neutralisation of $ CH_3COOH $ with strong base is $ -12.5,kcalmo{{l}^{-1}} $ . The enthalpy of ionisation of $ NH_4OH $ will be

Options:

A) $ 3.2kcalmo{{l}^{-1}} $

B) $ 2.0kcalmo{{l}^{-1}} $

C) $ 3.0kcalmo{{l}^{-1}} $

D) $ 4.0kcalmo{{l}^{-1}} $

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ {\Delta_{neu}}H $ for strong base and strong acid $ =-13.7kcal,e{{q}^{-1}} $

$ \Delta H_{ion}(CH_3COOH) $

$ =-12.5-( -13.7 )=1.2kcalmo{{l}^{-1}} $

$ \Delta H_{ion}(NH_4OH) $

$ =-10.5-(-13.7)-\Delta H_{ion}(CH_3COOH) $

$ =13.7-10.5-1.2 $

$ =2kcal,mo{{l}^{-1}} $



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