Chemical Thermodynamics Question 373
Question: The enthalpy of the reaction forming $ PbO $ according to the following equation is $ 438kJ $ . What heat energy (kJ) is released in formation of $ 22.3g,PbO( s ) $ - (Atomic masses: $ Pb=207,\text{ O}=16.0 $ ) $ 2Pb( s )+O_2( g )\xrightarrow{{}}2PbO( s ) $
Options:
A) 21.9
B) 28.7
C) 14.6
D) 34.2
Show Answer
Answer:
Correct Answer: A
Solution:
- $ Q=\frac{1}{2}438\times \frac{22.3}{223}=21.9,KJ $
