Chemical Thermodynamics Question 373

Question: The enthalpy of the reaction forming $ PbO $ according to the following equation is $ 438kJ $ . What heat energy (kJ) is released in formation of $ 22.3g,PbO( s ) $ - (Atomic masses: $ Pb=207,\text{ O}=16.0 $ ) $ 2Pb( s )+O_2( g )\xrightarrow{{}}2PbO( s ) $

Options:

A) 21.9

B) 28.7

C) 14.6

D) 34.2

Show Answer

Answer:

Correct Answer: A

Solution:

  • $ Q=\frac{1}{2}438\times \frac{22.3}{223}=21.9,KJ $


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