SATHEE: Chemical Thermodynamics Question 335

Chemical Thermodynamics Question 335

Question: One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) $\to$ (4.0 atm, 5.0 L, 245 K) with a change in internal energy, $Δ U = 30.0 L$ atm. The change in enthalpy $Δ H$ of the process in L atm is.

Options:

A) 40.0

B) 42.3

C) 44.0

D) Not defined because pressure is not constant

Show Answer

Answer:

Correct Answer: C

Solution:

$Δ H = H_{2} - H_{1} = (E_{2} + P_{2} V_{2}) - (E_{1} + P_{1} V_{1})$

$= (E_{2} - E_{1}) + (P_{2} V_{2} - P_{1} V_{1})$

$= 30 + (4 \times 5 - 2 \times 3) = 44 L$ atm

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Chemical Thermodynamics Question 335

Question: One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) → (4.0 atm, 5.0 L, 245 K) with a change in internal energy, ΔU=30.0L atm. The change in enthalpy ΔH of the process in L atm is.

Options:

Answer:

Solution:

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Question: One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) $\to$ (4.0 atm, 5.0 L, 245 K) with a change in internal energy, $Δ U = 30.0 L$ atm. The change in enthalpy $Δ H$ of the process in L atm is.