Chemical Thermodynamics Question 335
Question: One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.0 L, 95 K) $ \to $ (4.0 atm, 5.0 L, 245 K) with a change in internal energy, $ \Delta U=30.0L $ atm. The change in enthalpy $ \Delta H $ of the process in L atm is.
Options:
A) 40.0
B) 42.3
C) 44.0
D) Not defined because pressure is not constant
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Answer:
Correct Answer: C
Solution:
$ \Delta H=H_2-H_1=( E_2+P_2V_2 )-( E_1+P_1V_1 ) $
$ =(E_2-E_1)+(P_2V_2-P_1V_1) $
$ =30+( 4\times 5-2\times 3 )=44L $ atm
