Chemical Thermodynamics Question 320

Question: The enthalpies of combustion of carbon and carbon monoxide are -390 kJ and -278 kJ respectively. The enthalpy of formation of CO in kJ is

Options:

A) 668

B) 112

C) -112

D) -668

Show Answer

Answer:

Correct Answer: C

Solution:

  • $ C+O_2\to CO_2;\Delta H=-290kJ $ (1) $ CO+\frac{1}{2}O_2\to CO_2;\Delta H=-278,kJ $ (2) By eq. (1) and eq. (2), we get $ C+\frac{1}{2}O_2\to CO;\Delta H=-112,kJ $


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