Chemical Thermodynamics Question 320
Question: The enthalpies of combustion of carbon and carbon monoxide are -390 kJ and -278 kJ respectively. The enthalpy of formation of CO in kJ is
Options:
A) 668
B) 112
C) -112
D) -668
Show Answer
Answer:
Correct Answer: C
Solution:
- $ C+O_2\to CO_2;\Delta H=-290kJ $ (1) $ CO+\frac{1}{2}O_2\to CO_2;\Delta H=-278,kJ $ (2) By eq. (1) and eq. (2), we get $ C+\frac{1}{2}O_2\to CO;\Delta H=-112,kJ $
