Chemical Thermodynamics Question 303
Question: For complete neutralization of $ HCl $ with $ NaOH, $ the heat of neutralization is [MP PET 2003]
Options:
A) $ +13.70,kJ,mo{{l}^{-1}} $
B) $ -13.70,kJ,mo{{l}^{-1}} $
C) $ -57.32,kJ,mo{{l}^{-1}} $
D) $ +57.32,kJ,mo{{l}^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
Heat of neutralization of strong acid and strong base is equal to the $ -57.32,KJ,mo{{l}^{-1}} $
