Chemical Thermodynamics Question 303

Question: For complete neutralization of $ HCl $ with $ NaOH, $ the heat of neutralization is [MP PET 2003]

Options:

A) $ +13.70,kJ,mo{{l}^{-1}} $

B) $ -13.70,kJ,mo{{l}^{-1}} $

C) $ -57.32,kJ,mo{{l}^{-1}} $

D) $ +57.32,kJ,mo{{l}^{-1}} $

Show Answer

Answer:

Correct Answer: C

Solution:

Heat of neutralization of strong acid and strong base is equal to the $ -57.32,KJ,mo{{l}^{-1}} $



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