Chemical Thermodynamics Question 291

Question: The heat evolved in the combustion of methane is given by the following equations: $ CH_4(g)+2O_2(g),\to ,CO_2(g)+H_2O(l); $

$ \Delta H=-890.3,kJ $ How many grams of methane would be required to produce 445.15 kJ of heat of combustion [AMU 2002]

Options:

A) 4 g

B) 8 g

C) 12 g

D) 16 g

Show Answer

Answer:

Correct Answer: B

Solution:

$ CH_4 $ required $ =\frac{445.15\times 16}{890.3}=8gm $ .



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