Chemical Thermodynamics Question 291
Question: The heat evolved in the combustion of methane is given by the following equations: $ CH_4(g)+2O_2(g),\to ,CO_2(g)+H_2O(l); $
$ \Delta H=-890.3,kJ $ How many grams of methane would be required to produce 445.15 kJ of heat of combustion [AMU 2002]
Options:
A) 4 g
B) 8 g
C) 12 g
D) 16 g
Show Answer
Answer:
Correct Answer: B
Solution:
$ CH_4 $ required $ =\frac{445.15\times 16}{890.3}=8gm $ .
