SATHEE: Chemical Thermodynamics Question 272

Chemical Thermodynamics Question 272

Question: The $Δ H_{f}^{o}$ for $C O_{2} (g),, C O (g)$ and $H_{2} O (g)$ are - 393.5, -110.5 and - 241.8kJmol-1 respectively. The standard enthalpy change (in kJ) for the reaction $C O_{2} (g) + H_{2} (g) \to$

$C O (g) + H_{2} O (g)$ is [IIT JEE (Screening) 2000]

Options:

A) 524.1

B) 41.2

C) - 262.5

D) - 41.2

Show Answer

Answer:

Correct Answer: B

Solution:

$C + O_{2} \to C O_{2 (g)},, Δ H_{f}^{o} = - 393.5, k J, m o l^{- 1}$ -.(i) $C + \frac{1}{2} O_{2} \to C O_{(g)},, Δ H_{f}^{o} = - 110.5, k J, m o l^{- 1}$ -.(ii) $H_{2} + \frac{1}{2} O_{2} \to H_{2} O_{(g)},, Δ H_{f}^{o}$

$= - 241.8, k J m o l^{- 1}$ …(iii) By (ii) + (iii) - (i) $C O_{2 (g)} + H_{2 (g)} \to C O_{(g)} + H_{2} O_{(g)},, Δ H = + 41.2$ .

Play Store

App Store

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Chemical Thermodynamics Question 272

Question: The ΔHfo for CO2(g),,CO(g) and H2O(g) are - 393.5, -110.5 and - 241.8kJmol-1 respectively. The standard enthalpy change (in kJ) for the reaction CO2(g)+H2(g)→

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Menu

Question: The $Δ H_{f}^{o}$ for $C O_{2} (g),, C O (g)$ and $H_{2} O (g)$ are - 393.5, -110.5 and - 241.8kJmol-1 respectively. The standard enthalpy change (in kJ) for the reaction $C O_{2} (g) + H_{2} (g) \to$