Chemical Thermodynamics Question 272

Question: The $ \Delta H_{f}^{o} $ for $ CO_2(g),,CO(g) $ and $ H_2O(g) $ are - 393.5, -110.5 and - 241.8kJmol-1 respectively. The standard enthalpy change (in kJ) for the reaction $ CO_2(g)+H_2(g)\to $

$ CO(g)+H_2O(g) $ is [IIT JEE (Screening) 2000]

Options:

A) 524.1

B) 41.2

C) - 262.5

D) - 41.2

Show Answer

Answer:

Correct Answer: B

Solution:

$ C+O_2\to C{O_{2(g)}},,\Delta H_{f}^{o}=-393.5,kJ,mo{{l}^{-1}} $ -.(i) $ C+\frac{1}{2}O_2\to C{O_{(g)}},,\Delta H_{f}^{o}=-110.5,kJ,mo{{l}^{-1}} $ -.(ii) $ H_2+\frac{1}{2}O_2\to H_2{O_{(g)}},,\Delta H_{f}^{o} $

$ =-241.8,kJmo{{l}^{-1}} $ …(iii) By (ii) + (iii) - (i) $ C{O_{2(g)}}+{H_{2(g)}}\to C{O_{(g)}}+H_2{O_{(g)}},,\Delta H=+41.2 $ .



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