Chemical Thermodynamics Question 267
Question: Enthalpy of neutralisation of acetic acid by $ NaOH $ is $ -50.6,kJ/mol. $ and the heat of neutralisation of a strong acid with a strong base is - 55.9 kJ/mol. What is the value of $ \Delta H $ for the ionisation of $ CH_3COOH $ [AIIMS 2000]
Options:
A) + 5.3 kJ/mol
B) + 6.2 kJ/mol
C) + 8.2 kJ/mol
D) + 9.3 kJ/mol
Show Answer
Answer:
Correct Answer: A
Solution:
$ \Delta H=,\Delta {H_{ioniz}}+\Delta {H_{neu}} $ = $ -,50.6=,\Delta {H_{ioniz}}+(-55.9) $
$ \Delta {H_{ioniz}}=+,5.3,kJ/mol $ .
