Chemical Thermodynamics Question 267

Question: Enthalpy of neutralisation of acetic acid by $ NaOH $ is $ -50.6,kJ/mol. $ and the heat of neutralisation of a strong acid with a strong base is - 55.9 kJ/mol. What is the value of $ \Delta H $ for the ionisation of $ CH_3COOH $ [AIIMS 2000]

Options:

A) + 5.3 kJ/mol

B) + 6.2 kJ/mol

C) + 8.2 kJ/mol

D) + 9.3 kJ/mol

Show Answer

Answer:

Correct Answer: A

Solution:

$ \Delta H=,\Delta {H_{ioniz}}+\Delta {H_{neu}} $ = $ -,50.6=,\Delta {H_{ioniz}}+(-55.9) $

$ \Delta {H_{ioniz}}=+,5.3,kJ/mol $ .



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