Chemical Thermodynamics Question 225
Question: Based on the following thermochemical equations $ H_2O(g)+C(s)\to CO(g)+H_2(g);,\Delta H=131,kJ $
$ CO(g)+\frac{1}{2}O_2(g)\to CO_2(g);\Delta H=-282,kJ $
$ H_2(g)+\frac{1}{2}O_2(g)\to H_2O(g);,\Delta H=-242,kJ $
$ C(s)+O_2(g)\to CO_2(g);,\Delta H=X,kJ $ The value of $ X $ is [CBSE PMT 1992]
Options:
A) $ -393,kJ $
B) $ -,655,kJ $
C) $ +,393,kJ $
D) $ +655,kJ $
Show Answer
Answer:
Correct Answer: A
Solution:
eq. (i) + eq. (ii) + eq. (iii) gives $ X=131-282-242=-,393,kJ $ .
