Chemical Thermodynamics Question 225

Question: Based on the following thermochemical equations $ H_2O(g)+C(s)\to CO(g)+H_2(g);,\Delta H=131,kJ $

$ CO(g)+\frac{1}{2}O_2(g)\to CO_2(g);\Delta H=-282,kJ $

$ H_2(g)+\frac{1}{2}O_2(g)\to H_2O(g);,\Delta H=-242,kJ $

$ C(s)+O_2(g)\to CO_2(g);,\Delta H=X,kJ $ The value of $ X $ is [CBSE PMT 1992]

Options:

A) $ -393,kJ $

B) $ -,655,kJ $

C) $ +,393,kJ $

D) $ +655,kJ $

Show Answer

Answer:

Correct Answer: A

Solution:

eq. (i) + eq. (ii) + eq. (iii) gives $ X=131-282-242=-,393,kJ $ .



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक