Chemical Thermodynamics Question 162

Question: Molar heat of vaporisation of a liquid is $ 6kJ,mo{{l}^{-1}} $ . If the entropy change is $ 16J,mo{{l}^{-1}},{{K}^{-1}} $ , the boiling point of the liquid is [KCET 2005]

Options:

A) $ 375^{o}C $

B) $ 375K $

C) $ 273K $

D) $ 102^{o}C $

Show Answer

Answer:

Correct Answer: B

Solution:

$ \Delta S=16J,mol{{e}^{-1}}{{K}^{-1}} $

$ {T_{b.p.}}=\frac{\Delta {H_{vapour}}}{\Delta {S_{vapour}}}=\frac{6\times 1000}{16}=375K $



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