Chemical Thermodynamics Question 162
Question: Molar heat of vaporisation of a liquid is $ 6kJ,mo{{l}^{-1}} $ . If the entropy change is $ 16J,mo{{l}^{-1}},{{K}^{-1}} $ , the boiling point of the liquid is [KCET 2005]
Options:
A) $ 375^{o}C $
B) $ 375K $
C) $ 273K $
D) $ 102^{o}C $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta S=16J,mol{{e}^{-1}}{{K}^{-1}} $
$ {T_{b.p.}}=\frac{\Delta {H_{vapour}}}{\Delta {S_{vapour}}}=\frac{6\times 1000}{16}=375K $
