Chemical Thermodynamics Question 150

Question: For a reaction at $ 25^{o}C $ enthalpy change and entropy changes are $ -11.7\times 10^{3}J,mo{{l}^{-1}} $ and $ -105,J,mo{{l}^{-1}}{{K}^{-1}} $ respectively. What is the Gibbs free energy [BHU 2001]

Options:

A) 15.05 kJ

B) 19.59 kJ

C) 2.55 kJ

D) 22.55 kJ

Show Answer

Answer:

Correct Answer: B

Solution:

$ \Delta G=\Delta H-T\Delta S,,T=25+273=298K $

$ =-11.7\times 10^{3}-298\times (-105)=19590J=19.59kJ $



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