Chemical Thermodynamics Question 150
Question: For a reaction at $ 25^{o}C $ enthalpy change and entropy changes are $ -11.7\times 10^{3}J,mo{{l}^{-1}} $ and $ -105,J,mo{{l}^{-1}}{{K}^{-1}} $ respectively. What is the Gibbs free energy [BHU 2001]
Options:
A) 15.05 kJ
B) 19.59 kJ
C) 2.55 kJ
D) 22.55 kJ
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta G=\Delta H-T\Delta S,,T=25+273=298K $
$ =-11.7\times 10^{3}-298\times (-105)=19590J=19.59kJ $
