Chemical Thermodynamics Question 132

Question: For the gaseous reaction, $ N_2O_4\to 2NO_2 $ [Pb. CET 2003]

Options:

A) $ \Delta H<\Delta E $

B) $ \Delta H=\Delta E $

C) $ \Delta H=0 $

D) $ \Delta H>\Delta E $

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Answer:

Correct Answer: D

Solution:

$ N_2O_4(g)\to 2NO_2(g) $ For this reaction $ \Delta ng=2-1=1 $

$ \Delta ng $ is positive i.e., there is an increase in the number of gaseous moles then $ \Delta H>\Delta E $



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