Chemical Thermodynamics Question 132
Question: For the gaseous reaction, $ N_2O_4\to 2NO_2 $ [Pb. CET 2003]
Options:
A) $ \Delta H<\Delta E $
B) $ \Delta H=\Delta E $
C) $ \Delta H=0 $
D) $ \Delta H>\Delta E $
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Answer:
Correct Answer: D
Solution:
$ N_2O_4(g)\to 2NO_2(g) $ For this reaction $ \Delta ng=2-1=1 $
$ \Delta ng $ is positive i.e., there is an increase in the number of gaseous moles then $ \Delta H>\Delta E $
