Chemical Thermodynamics Question 110

Question: The relation between change in internal energy $ (\Delta E) $ , change in enthalpy $ (\Delta H) $ and work done (W) is represented as [AFMC 1999]

Options:

A) $ \Delta H=\Delta E+W $

B) $ W=\Delta E-\Delta H $

C) $ \Delta E=W-\Delta H $

D) $ \Delta E=\Delta H+W $

Show Answer

Answer:

Correct Answer: A

Solution:

$ \Delta H=\Delta E+Wor\Delta H=\Delta E+P\Delta V $ .



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