Chemical Thermodynamics Question 110
Question: The relation between change in internal energy $ (\Delta E) $ , change in enthalpy $ (\Delta H) $ and work done (W) is represented as [AFMC 1999]
Options:
A) $ \Delta H=\Delta E+W $
B) $ W=\Delta E-\Delta H $
C) $ \Delta E=W-\Delta H $
D) $ \Delta E=\Delta H+W $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \Delta H=\Delta E+Wor\Delta H=\Delta E+P\Delta V $ .
