Chemical Kinetics Question 37

Question: Activation energy of a chemical reaction can be determined by [CBSE PMT 1998; AFMC 1999; BHU 2000]

Options:

A) Changing concentration of reactants

B) Evaluating rate constant at standard temperature

C) Evaluating rate constants at two different temperatures

D) Evaluating velocities of reaction at two different temperatures

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Answer:

Correct Answer: C

Solution:

$ \log \frac{K_2}{K_1}=\frac{E_{a}}{2.303R}[ \frac{T_2-T_1}{T_1T_2} ] $



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