Chemical Kinetics Question 37
Question: Activation energy of a chemical reaction can be determined by [CBSE PMT 1998; AFMC 1999; BHU 2000]
Options:
A) Changing concentration of reactants
B) Evaluating rate constant at standard temperature
C) Evaluating rate constants at two different temperatures
D) Evaluating velocities of reaction at two different temperatures
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Answer:
Correct Answer: C
Solution:
$ \log \frac{K_2}{K_1}=\frac{E_{a}}{2.303R}[ \frac{T_2-T_1}{T_1T_2} ] $
