Chemical Kinetics Question 338
Question: The rate constant of a reaction with a virus is $ 3.3\times {10^{-4}}{s^{-1}} $ . Time required for the virus to become 75% inactivated is
Options:
A) 35 min
B) 70 min
C) 105 min
D) 17.5 min
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ {t_{1/2}}=\frac{0.693}{k}=2100s=35,min $
$ t_{75} $ % $ =2{t_{1/2}}=2\times 35=70,min $
