Chemical Kinetics Question 338

Question: The rate constant of a reaction with a virus is $ 3.3\times {10^{-4}}{s^{-1}} $ . Time required for the virus to become 75% inactivated is

Options:

A) 35 min

B) 70 min

C) 105 min

D) 17.5 min

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $ {t_{1/2}}=\frac{0.693}{k}=2100s=35,min $

$ t_{75} $ % $ =2{t_{1/2}}=2\times 35=70,min $



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