Chemical Kinetics Question 333

Question: In a reaction at $ 27{}^\circ C,{10^{-3}} $ % reactant molecules manage to cross over the barrier of transition state. The energy of these molecules in excess of the average value will be $ (R=2cal{K^{-1}}mo{l^{-1}}) $ :

Options:

A) $ 6.91\text{ kc}almo{l^{-1}} $

B) $ 3.00\text{ kc}almo{l^{-1}} $

C) $ 4.15,kcal,mo{l^{-1}} $

D) $ 5.10kcal,mo{l^{-1}} $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ {e^{-E_{a}/RT}}={10^{-3}} $ % $ ={10^{-5}}; $

$ E_{a}=2.303\times 2\times 300\times 5,cal $

$ =6.91 kcal/mo{l^{-1}} $



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