Chemical Kinetics Question 333
Question: In a reaction at $ 27{}^\circ C,{10^{-3}} $ % reactant molecules manage to cross over the barrier of transition state. The energy of these molecules in excess of the average value will be $ (R=2cal{K^{-1}}mo{l^{-1}}) $ :
Options:
A) $ 6.91\text{ kc}almo{l^{-1}} $
B) $ 3.00\text{ kc}almo{l^{-1}} $
C) $ 4.15,kcal,mo{l^{-1}} $
D) $ 5.10kcal,mo{l^{-1}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ {e^{-E_{a}/RT}}={10^{-3}} $ % $ ={10^{-5}}; $
$ E_{a}=2.303\times 2\times 300\times 5,cal $
$ =6.91 kcal/mo{l^{-1}} $
