Chemical Kinetics Question 33
Question: The rate constant $ ({K}’) $ of one reaction is double of the rate constant $ ({K}’’) $ of another reaction. Then the relationship between the corresponding activation energies of the two reactions ( $ E_a^{\prime } $ and $ E_a^{\prime\prime } $ ) will be [MP PET 1994; UPSEAT 2001]
Options:
A) $ E_a^{\prime }>E_a^{\prime\prime } $
B) $ E_a^{\prime }=E_a^{\prime\prime } $
C) $ E_a^{\prime }<E_a^{\prime\prime } $
D) $ E_a^{\prime }=4E_a^{\prime\prime } $
Show Answer
Answer:
Correct Answer: C
Solution:
As $ {K^{’}}>{K^{’’}},E_a^{’}<E_a^{’’} $ (Greater the rate constant, less is the activation energy).
