Chemical Kinetics Question 28

Question: If $ 3A\to 2B, $ then the rate of reaction of $ +\frac{d(B)}{dt} $ is equal to [CBSE PMT 2002]

Options:

A) $ +2\frac{d(A)}{dt} $

B) $ -\frac{1}{3}\frac{d(A)}{dt} $

C) $ -\frac{2}{3}\frac{d(A)}{dt} $

D) $ -\frac{3}{2}\frac{d(A)}{dt} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ -\frac{1}{3}\frac{d[A]}{dt}=\frac{1}{2}\frac{d[B]}{dt} $
$ \therefore \frac{d[B]}{dt}=-\frac{2}{3}\frac{d[A]}{dt} $



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