Chemical Kinetics Question 28
Question: If $ 3A\to 2B, $ then the rate of reaction of $ +\frac{d(B)}{dt} $ is equal to [CBSE PMT 2002]
Options:
A) $ +2\frac{d(A)}{dt} $
B) $ -\frac{1}{3}\frac{d(A)}{dt} $
C) $ -\frac{2}{3}\frac{d(A)}{dt} $
D) $ -\frac{3}{2}\frac{d(A)}{dt} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ -\frac{1}{3}\frac{d[A]}{dt}=\frac{1}{2}\frac{d[B]}{dt} $
$ \therefore \frac{d[B]}{dt}=-\frac{2}{3}\frac{d[A]}{dt} $
