SATHEE: Chemical Kinetics Question 28

Chemical Kinetics Question 28

Question: If $3 A \to 2 B,$ then the rate of reaction of $+ \frac{d (B)}{d t}$ is equal to [CBSE PMT 2002]

Options:

A) $+ 2 \frac{d (A)}{d t}$

B) $- \frac{1}{3} \frac{d (A)}{d t}$

C) $- \frac{2}{3} \frac{d (A)}{d t}$

D) $- \frac{3}{2} \frac{d (A)}{d t}$

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Answer:

Correct Answer: C

Solution:

$- \frac{1}{3} \frac{d [A]}{d t} = \frac{1}{2} \frac{d [B]}{d t}$
$∴ \frac{d [B]}{d t} = - \frac{2}{3} \frac{d [A]}{d t}$

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Chemical Kinetics Question 28

Question: If 3A→2B, then the rate of reaction of +d(B)dt is equal to [CBSE PMT 2002]

Options:

Answer:

Solution:

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Question: If $3 A \to 2 B,$ then the rate of reaction of $+ \frac{d (B)}{d t}$ is equal to [CBSE PMT 2002]