SATHEE: Chemical Kinetics Question 271

Chemical Kinetics Question 271

Question: Rate constant $k = 1.2 \times 10^{3} m o l^{- 1}, L, s^{- 1}$ and $E_{a} = 2.0 \times 10^{2}, k J, m o l^{- 1}$ When $T \to \infty :$

Options:

A) $A = 2.0 \times 10^{2} k J, m o l^{- 1}$

B) $A = 1.2 \times 10^{3}, m o l^{- 1} L, S^{- 1}$

C) $A = 1.2 \times 10^{3} m o l, L^{- 1} s^{- 1}$

D) $A = 2.4 \times 10^{3} k J, m o l^{- 1} s^{- 1}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $k = A e^{- E_{a} / R T}$ If $T \overset{}{\to} \infty, k = A$

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