Chemical Kinetics Question 271
Question: Rate constant $ k=1.2\times 10^{3}mo{l^{-1}},L,{s^{-1}} $ and $ E_{a}=2.0\times 10^{2},kJ,mo{l^{-1}} $ When $ T\to \infty : $
Options:
A) $ A=2.0\times 10^{2}kJ,mo{l^{-1}} $
B) $ A=1.2\times 10^{3},mo{l^{-1}}L,{S^{-1}} $
C) $ A=1.2\times 10^{3}mol,{L^{-1}}{s^{-1}} $
D) $ A=2.4\times 10^{3}kJ,mo{l^{-1}}{s^{-1}} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ k=A{e^{-E_{a}/RT}} $ If $ T\xrightarrow{{}}\infty ,k=A $
