Chemical Kinetics Question 266

Question: For a first order reaction, a plot of log $ ( a-x ) $ against time is a straight line with a negative slope equal to

Options:

A) $ \frac{-k}{2.303} $

B) $ -2.303k $

C) $ \frac{2.303}{k} $

D) $ -\frac{E_{a}}{2.303R} $

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Answer:

Correct Answer: A

Solution:

[a] $ t=\frac{2.303}{k}\log \frac{a}{a-x} $ or $ t=\frac{2.303}{k}\log ,a-\frac{2.303}{k}\log (a-x) $

$ \log (a-x)=\frac{-k}{2.303}t+\log a $



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