Chemical Kinetics Question 266
Question: For a first order reaction, a plot of log $ ( a-x ) $ against time is a straight line with a negative slope equal to
Options:
A) $ \frac{-k}{2.303} $
B) $ -2.303k $
C) $ \frac{2.303}{k} $
D) $ -\frac{E_{a}}{2.303R} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ t=\frac{2.303}{k}\log \frac{a}{a-x} $ or $ t=\frac{2.303}{k}\log ,a-\frac{2.303}{k}\log (a-x) $
$ \log (a-x)=\frac{-k}{2.303}t+\log a $
