Chemical Kinetics Question 215

Question: $ {t_{\frac{1}{4}}} $ can be taken as the time taken for the concentration of a reactant to drop to $ \frac{3}{4} $ of its initial value. If the rate constant for a first order reaction is $ K $ , the $ {t_{\frac{1}{4}}} $ can be written as [AIEEE 2005]

Options:

A) $ 0.10/K $

B) $ 0.29/K $

C) $ 0.69/K $

D) $ 0.75/K $

Show Answer

Answer:

Correct Answer: B

Solution:

$ {t_{1/4}}=\frac{2.303}{K}\log \frac{1}{1-\frac{1}{4}}=\frac{0.29}{K} $ .



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