Chemical Kinetics Question 215
Question: $ {t_{\frac{1}{4}}} $ can be taken as the time taken for the concentration of a reactant to drop to $ \frac{3}{4} $ of its initial value. If the rate constant for a first order reaction is $ K $ , the $ {t_{\frac{1}{4}}} $ can be written as [AIEEE 2005]
Options:
A) $ 0.10/K $
B) $ 0.29/K $
C) $ 0.69/K $
D) $ 0.75/K $
Show Answer
Answer:
Correct Answer: B
Solution:
$ {t_{1/4}}=\frac{2.303}{K}\log \frac{1}{1-\frac{1}{4}}=\frac{0.29}{K} $ .
