Chemical Kinetics Question 192
Question: 75% of a first order reaction was completed in 32 minutes when was 50% of the reaction completed [AMU 1999; Kerala (Med.) 2003]
Options:
A) 16 min.
B) 24 min.
C) 8 min.
D) 4 min.
Show Answer
Answer:
Correct Answer: A
Solution:
$ k=\frac{2.303}{t}\log ( \frac{a}{a-x} ) $
$ k=\frac{2.303}{32}\log ( \frac{100}{100-75} ) $ .- (i) $ k=\frac{2.303}{t}\log ( \frac{100}{100-50} ) $ -.(ii) from the two equation (i) and (ii), $ t=16 $ minutes.
