SATHEE: Chemical Kinetics Question 192

Chemical Kinetics Question 192

Question: 75% of a first order reaction was completed in 32 minutes when was 50% of the reaction completed [AMU 1999; Kerala (Med.) 2003]

Options:

A) 16 min.

B) 24 min.

C) 8 min.

D) 4 min.

Show Answer

Answer:

Correct Answer: A

Solution:

$k = \frac{2.303}{t} \log (\frac{a}{a - x})$

$k = \frac{2.303}{32} \log (\frac{100}{100 - 75})$ .- (i) $k = \frac{2.303}{t} \log (\frac{100}{100 - 50})$ -.(ii) from the two equation (i) and (ii), $t = 16$ minutes.

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Chemical Kinetics Question 192

Question: 75% of a first order reaction was completed in 32 minutes when was 50% of the reaction completed [AMU 1999; Kerala (Med.) 2003]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Chemical Kinetics Question 192

Question: 75% of a first order reaction was completed in 32 minutes when was 50% of the reaction completed [AMU 1999; Kerala (Med.) 2003]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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