Chemical Kinetics Question 187
Question: The half-life period for a first order reaction is 693 seconds. The rate constants for this reaction would be [MP PET 2002]
Options:
A) $ 0.1se{c^{-1}} $
B) $ 0.01se{c^{-1}} $
C) $ 0.001se{c^{-1}} $
D) $ 0.0001se{c^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ {t_{1/2}}=\frac{0.693}{k} $ Given $ {t_{1/2}}=693\sec $
$ 693=\frac{0.693}{k} $ , $ k=\frac{693\times {10^{-3}}}{693} $ ; $ k={10^{-3}}=0.001{{\sec }^{-1}} $ .
