Chemical Kinetics Question 187

Question: The half-life period for a first order reaction is 693 seconds. The rate constants for this reaction would be [MP PET 2002]

Options:

A) $ 0.1se{c^{-1}} $

B) $ 0.01se{c^{-1}} $

C) $ 0.001se{c^{-1}} $

D) $ 0.0001se{c^{-1}} $

Show Answer

Answer:

Correct Answer: C

Solution:

$ {t_{1/2}}=\frac{0.693}{k} $ Given $ {t_{1/2}}=693\sec $

$ 693=\frac{0.693}{k} $ , $ k=\frac{693\times {10^{-3}}}{693} $ ; $ k={10^{-3}}=0.001{{\sec }^{-1}} $ .



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