Chemical Kinetics Question 152

Question: The half-life period of a first order reaction is 100 sec. The rate constant of the reaction is [MP PMT 1997; MP PET 2001]

Options:

A) $ 6.93\times {10^{-3}}{{\sec }^{-1}} $

B) $ 6.93\times {10^{-4}}{{\sec }^{-1}} $

C) $ 0.693,{{\sec }^{-1}} $

D) $ 69.3,{{\sec }^{-1}} $

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Answer:

Correct Answer: A

Solution:

$ k=\frac{0.693}{{t_{1/2}}}=\frac{0.693}{100\sec }=6.93\times {10^{-3}}se{c^{-1}} $



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