SATHEE: Chemical Kinetics Question 152

Chemical Kinetics Question 152

Question: The half-life period of a first order reaction is 100 sec. The rate constant of the reaction is [MP PMT 1997; MP PET 2001]

Options:

A) $6.93 \times 10^{- 3} \sec^{- 1}$

B) $6.93 \times 10^{- 4} \sec^{- 1}$

C) $0.693, \sec^{- 1}$

D) $69.3, \sec^{- 1}$

Show Answer

Answer:

Correct Answer: A

Solution:

$k = \frac{0.693}{t_{1 / 2}} = \frac{0.693}{100 \sec} = 6.93 \times 10^{- 3} s e c^{- 1}$

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