Chemical Kinetics Question 152
Question: The half-life period of a first order reaction is 100 sec. The rate constant of the reaction is [MP PMT 1997; MP PET 2001]
Options:
A) $ 6.93\times {10^{-3}}{{\sec }^{-1}} $
B) $ 6.93\times {10^{-4}}{{\sec }^{-1}} $
C) $ 0.693,{{\sec }^{-1}} $
D) $ 69.3,{{\sec }^{-1}} $
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Answer:
Correct Answer: A
Solution:
$ k=\frac{0.693}{{t_{1/2}}}=\frac{0.693}{100\sec }=6.93\times {10^{-3}}se{c^{-1}} $
