SATHEE: Chemical Kinetics Question 146

Chemical Kinetics Question 146

Question: The half life for the reaction $N_{2} O_{5}$ ⇌ $2 N O_{2} + \frac{1}{2} O_{2}$ in $24, h r s$ at $30^{o} C$ . Starting with $10, g$ of $N_{2} O_{5}$ how many grams of $N_{2} O_{5}$ will remain after a period of 96 hours [KCET 1992]

Options:

A) $1.25, g$

B) $0.63, g$

C) $1.77, g$

D) $0.5, g$

Show Answer

Answer:

Correct Answer: B

Solution:

$k = \frac{0.693}{24} h r^{- 1} = \frac{2.303}{96} \log \frac{10}{a - x}$ or $\log \frac{10}{a - x} = 1.2036$ or 1 - log (a - x) = 1.2036 or $\log (a - x) = - 0.2036 = 1.7964$ or $(a - x) = a n t i l o g 1, .7964 = 0.6258, g m$

Chemical Kinetics Question 146

Question: The half life for the reaction $N_{2} O_{5}$ ⇌ $2 N O_{2} + \frac{1}{2} O_{2}$ in $24, h r s$ at $30^{o} C$ . Starting with $10, g$ of $N_{2} O_{5}$ how many grams of $N_{2} O_{5}$ will remain after a period of 96 hours [KCET 1992]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

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Sample Mock Test

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NCERT Exercise Video Solution

Chemical Kinetics Question 146

Question: The half life for the reaction N2O5 ⇌ 2NO2+12O2 in 24,hrs at 30oC . Starting with 10,g of N2O5 how many grams of N2O5 will remain after a period of 96 hours [KCET 1992]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The half life for the reaction $N_{2} O_{5}$ ⇌ $2 N O_{2} + \frac{1}{2} O_{2}$ in $24, h r s$ at $30^{o} C$ . Starting with $10, g$ of $N_{2} O_{5}$ how many grams of $N_{2} O_{5}$ will remain after a period of 96 hours [KCET 1992]