Chemical Kinetics Question 146

Question: The half life for the reaction $ N_2O_5 $ ⇌ $ 2NO_2+\frac{1}{2}O_2 $ in $ 24,hrs $ at $ 30^{o}C $ . Starting with $ 10,g $ of $ N_2O_5 $ how many grams of $ N_2O_5 $ will remain after a period of 96 hours [KCET 1992]

Options:

A) $ 1.25,g $

B) $ 0.63,g $

C) $ 1.77,g $

D) $ 0.5,g $

Show Answer

Answer:

Correct Answer: B

Solution:

$ k=\frac{0.693}{24}h{r^{-1}}=\frac{2.303}{96}\log \frac{10}{a-x} $ or $ \log \frac{10}{a-x}=1.2036 $ or 1 - log (a - x) = 1.2036 or $ \log (a-x)=-0.2036=1.7964 $ or $ (a-x)=antilog1,.7964=0.6258,gm $



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