Chemical Bonding And Molecular Structure Question 426
Question: Molecular AB has a bond length of $ 1.61\overset{o}{\mathop{A}}, $ and a dipole moment of 0.38 D. The fractional charge on each atom (absolute magnitude) is: $ (e=4.802\times {10^{-10}}esu) $
Options:
A) 0.5
B) 0.05
C) 0
D) 1.0
Show Answer
Answer:
Correct Answer: B
Solution:
- $ 1e=1.602\times {10^{-19}}C $
$ 1,esu=3.33\times {10^{-10}}C $
$ \frac{1e}{1,esu}=\frac{1.602\times {10^{-19}}C}{3.33\times {10^{-10}}C} $
$ 1e=4.802\times {10^{-10}}esu $
$ Dipolemoment=q\times distance $
$ \Rightarrow 1,D\approx {10^{-18}}esucm $
$ 0.38\times {10^{-18}}esu,cm=q\times (1.61\times {10^{-18}}cm) $
$ q=2.36\times {10^{-11}}esu $
$ q=\frac{2.36\times {10^{-11}}esu}{4.802\times {10^{-10}}esu} $
$ q=0.049 $
$ q\approx 0.05 $ fractional charge
