Chemical Bonding And Molecular Structure Question 426

Question: Molecular AB has a bond length of $ 1.61\overset{o}{\mathop{A}}, $ and a dipole moment of 0.38 D. The fractional charge on each atom (absolute magnitude) is: $ (e=4.802\times {10^{-10}}esu) $

Options:

A) 0.5

B) 0.05

C) 0

D) 1.0

Show Answer

Answer:

Correct Answer: B

Solution:

  • $ 1e=1.602\times {10^{-19}}C $

$ 1,esu=3.33\times {10^{-10}}C $

$ \frac{1e}{1,esu}=\frac{1.602\times {10^{-19}}C}{3.33\times {10^{-10}}C} $

$ 1e=4.802\times {10^{-10}}esu $

$ Dipolemoment=q\times distance $
$ \Rightarrow 1,D\approx {10^{-18}}esucm $

$ 0.38\times {10^{-18}}esu,cm=q\times (1.61\times {10^{-18}}cm) $

$ q=2.36\times {10^{-11}}esu $

$ q=\frac{2.36\times {10^{-11}}esu}{4.802\times {10^{-10}}esu} $

$ q=0.049 $

$ q\approx 0.05 $ fractional charge



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